-(2x^2)+2x-1=0

Solution for -(2x^2)+2x-1=0 equation:

Simplifying
-1(2x2) + 2x + -1 = 0

Remove parenthesis around (2x2)
-1 * 2x2 + 2x + -1 = 0

Multiply -1 * 2
-2x2 + 2x + -1 = 0

Reorder the terms:
-1 + 2x + -2x2 = 0

Solving
-1 + 2x + -2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-2 the coefficient of the squared term: 

Divide each side by '-2'.
0.5 + -1x + x2 = 0

Move the constant term to the right:

Add '-0.5' to each side of the equation.
0.5 + -1x + -0.5 + x2 = 0 + -0.5

Reorder the terms:
0.5 + -0.5 + -1x + x2 = 0 + -0.5

Combine like terms: 0.5 + -0.5 = 0.0
0.0 + -1x + x2 = 0 + -0.5
-1x + x2 = 0 + -0.5

Combine like terms: 0 + -0.5 = -0.5
-1x + x2 = -0.5

The x term is -1x.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1x + 0.25 + x2 = -0.5 + 0.25

Reorder the terms:
0.25 + -1x + x2 = -0.5 + 0.25

Combine like terms: -0.5 + 0.25 = -0.25
0.25 + -1x + x2 = -0.25

Factor a perfect square on the left side:
(x + -0.5)(x + -0.5) = -0.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.